Mister Exam
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How to use it?
How do you in partial fractions?
:
-2/(x*x^2)
1/(2*x^2)
(x+5)/(x^2+22*x+85)
y/(y+3)^2-y/(y^2)-9
Factor polynomial
:
x^2-64
-y^3-5*x^2*y+x^4+5*x^4-7*x^2*y+6*y^3
x^5-32
x^2+x-y^2-y
Least common denominator
:
(234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
(((z)/(b))-((b)/(z)))*((4*z*b)/(z+b))
(z-3)/(z+3)*(z+(z^2)/(3-z))
y/(y+3)^2-y/(y^2)-9
Factor squared
:
y^4+9*y^2+8
-y^2-2*y*b+b^2
x^2+x+6
-y^4-y^2+2
Integral of d{x}
:
1/(2*x^2)
Limit of the function
:
1/(2*x^2)
Derivative of
:
1/(2*x^2)
Identical expressions
one /(two *x^ two)
1 divide by (2 multiply by x squared )
one divide by (two multiply by x to the power of two)
1/(2*x2)
1/2*x2
1/(2*x²)
1/(2*x to the power of 2)
1/(2x^2)
1/(2x2)
1/2x2
1/2x^2
1 divide by (2*x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(2*x^2)
How do you 1/(2*x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ---- 2 2*x
$$\frac{1}{2 x^{2}}$$
1/(2*x^2)
Fraction decomposition
[src]
1/(2*x^2)
$$\frac{1}{2 x^{2}}$$
1 ---- 2 2*x
Numerical answer
[src]
0.5/x^2
0.5/x^2