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How to use it?
How do you in partial fractions?
:
2*(-1+(-1+x)/(2+x))/(2+x)^2
(1+(1+(1+x)/(1-3x))/(1-3\(1+x)/(1-3x)))/(-3\(1+(1+x)/(1-3x))/(1-3\(1+x)/(1-3x)))
y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
(c^4-3*c^2+2)/(c^5+1)
Factor polynomial
:
x^2-4
x-x^2
x^8+1
x^6-8
Least common denominator
:
(2*a+b)/(a^2-b^2)+1/(a+b)
(234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
(z/x-z+x+z/z)/x/x^2-z^2
(z/x-z+x+z/z)/x/x^2-x*z^2
Factor squared
:
y^4-y^2+15
y^4-y^2-3
y^4-12*y^2+7
-y^2+4*y+3
Integral of d{x}
:
1/(2*x^2)
Limit of the function
:
1/(2*x^2)
Derivative of
:
1/(2*x^2)
Identical expressions
one /(two *x^ two)
1 divide by (2 multiply by x squared )
one divide by (two multiply by x to the power of two)
1/(2*x2)
1/2*x2
1/(2*x²)
1/(2*x to the power of 2)
1/(2x^2)
1/(2x2)
1/2x2
1/2x^2
1 divide by (2*x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(2*x^2)
How do you 1/(2*x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ---- 2 2*x
$$\frac{1}{2 x^{2}}$$
1/(2*x^2)
Fraction decomposition
[src]
1/(2*x^2)
$$\frac{1}{2 x^{2}}$$
1 ---- 2 2*x
Numerical answer
[src]
0.5/x^2
0.5/x^2