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How to use it?
How do you in partial fractions?
:
(2x-1)/(x*(x+2)^2*(x-4))
(z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
(m^2-1)/(m+1)
1/(2*x^2)
Factor polynomial
:
x^3+y^3
x^2-3*x+2
x^3-x^2-x-2
x^3-x^2-x^3+2
Least common denominator
:
x^4/4+5*x^2/2-4*x
(pi*a^2+pi/4)/(pi*a^2+pi/2)
(a+4)*a/2+(4*a+16)/(4*a^2+a^3)
(5/s)*(2/((1/5)*s+1))*(1/(s+1))
Factor squared
:
-y^4-y^2-3
y^4+y^2+6
x^2+3*x+4
-y^4-y^2+4
Limit of the function
:
1/(2*x^2)
Integral of d{x}
:
1/(2*x^2)
Derivative of
:
1/(2*x^2)
Identical expressions
one /(two *x^ two)
1 divide by (2 multiply by x squared )
one divide by (two multiply by x to the power of two)
1/(2*x2)
1/2*x2
1/(2*x²)
1/(2*x to the power of 2)
1/(2x^2)
1/(2x2)
1/2x2
1/2x^2
1 divide by (2*x^2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(2*x^2)
How do you 1/(2*x^2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ---- 2 2*x
$$\frac{1}{2 x^{2}}$$
1/(2*x^2)
Fraction decomposition
[src]
1/(2*x^2)
$$\frac{1}{2 x^{2}}$$
1 ---- 2 2*x
Numerical answer
[src]
0.5/x^2
0.5/x^2