Mister Exam
Other calculators
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How to use it?
- Factor polynomial:
- x^2+x-2
- x^4-x^2
- y^3+y^6
- x^4-5*x^3+6*x^2-10*x+8
- Least common denominator:
- (a+4)*a/2+(4*a+16)/(4*a^2+a^3)
- ((3*c+1)/(c-1)+c)/(c+1)
- ((x^-6-64)/(4+2*x^-1+x^-2))*(x^2/(4-4/x+1/x^2))-(4*x^2*(2*x+1))/(1-2*x)
- factorial(5)/(m*(m+1))*factorial(m+1)/factorial(m-1)
- Factor squared:
- y^4-y^2-8
- -y^4-y^2-5
- -y^4-y^2-3
- -y^4+14*y^2-2
- How do you in partial fractions?:
- -x^2/(x-2)^2+2*x/(x-2)
- -1/(3*x^3)
- (1/(s+1))*(1/(s-1))
- ((6*p/(2*p-5))*4)/(1+((6*p/(2*p-5))/p)+(6*p/(2*p-5))*4*((-5)/p))*(2-7/4*p)/(1-7/4*p*6)
- Graphing y =:
-
x^2+x-2
- Canonical form:
- x^2+x-2
- Factor squared:
- x^2+x-2
-
Identical expressions
- x^ two +x- two
- x squared plus x minus 2
- x to the power of two plus x minus two
- x2+x-2
- x²+x-2
- x to the power of 2+x-2
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Similar expressions
- x^2+x+2
- x^2-x-2
Factor polynomial x^2+x-2
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$
$$\left(x^{2} + x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -2$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{9}{4}$$