Mister Exam
Other calculators
-
How to use it?
- Factor polynomial:
- x^4-16
- x^2-x-2
- x^2+x-2
- c^3-d^3
- Least common denominator:
- (a+4)*a/2+(4*a+16)/(4*a^2+a^3)
- ((3*c+1)/(c-1)+c)/(c+1)
- (z*(z^2+6*z+1)-(4*z*(z+1)))/(z-1)^3+z*(z-1)/(z+1)^3
- exp(x)/x^7-7*exp(x)/x^8
- Factor squared:
- -y^2-4*y+3
- y^4+y^2-3
- x^2+x-6
- -y^4-y^2-5
- How do you in partial fractions?:
- z/(z+4)^2-z/z^2-16
- -2*sqrt(3)/(3*sqrt(1-(2*x-1)^2/3))
- (3a^2-12)/(9a^3-72)
- 2/(x+2)-(2*x-6)/(x+2)^2
- Factor squared:
- x^2-x-2
- Integral of d{x}:
-
x^2-x-2
- Graphing y =:
- x^2-x-2
-
Identical expressions
- x^ two -x- two
- x squared minus x minus 2
- x to the power of two minus x minus two
- x2-x-2
- x²-x-2
- x to the power of 2-x-2
-
Similar expressions
- x^2+x-2
- x^2-x+2
Factor polynomial x^2-x-2
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = -2$$
Then
$$m = - \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} - \frac{9}{4}$$
$$\left(x^{2} - x\right) - 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = -2$$
Then
$$m = - \frac{1}{2}$$
$$n = - \frac{9}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} - \frac{9}{4}$$