Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
-1/(3*x^3)
(3a^2-12)/(9a^3-72)
z/(z+4)^2-z/z^2-16
-2*sqrt(3)/(3*sqrt(1-(2*x-1)^2/3))
Factor polynomial:
x^8-1
a^8-b^8
x^2-y^2+x-y
x^3+y^6
Least common denominator:
(x^3+12*x)*(x/(2*(x^3+12*x))+(-12-3*x^2)*(x^2+4)/(4*(x^3+12*x)^2))/(x^2+4)
(sin(4*x)/((2+2*x)*8)+sin(2*x)/2+x/2)/2
(sin(2*x)/2+x)/2
(c*(v/k+1)+t)/((n+k)*(v/k+1)-k)
Factor squared:
-y^2+4*y-3
x^2+9*x-5
y^4-y^2-8
-y^4+y^2-7
Identical expressions
(three a^ two - twelve)/(9a^3- seventy-two)
(3a squared minus 12) divide by (9a cubed minus 72)
(three a to the power of two minus twelve) divide by (9a cubed minus seventy minus two)
(3a2-12)/(9a3-72)
3a2-12/9a3-72
(3a²-12)/(9a³-72)
(3a to the power of 2-12)/(9a to the power of 3-72)
3a^2-12/9a^3-72
(3a^2-12) divide by (9a^3-72)
Similar expressions
(3a^2+12)/(9a^3-72)
(3a^2-12)/(9a^3+72)

How do you (3a^2-12)/(9a^3-72) in partial fractions?

You have entered [src]

   2     
3*a  - 12
---------
   3     
9*a  - 72

$$\frac{3 a^{2} - 12}{9 a^{3} - 72}$$

(3*a^2 - 12)/(9*a^3 - 72)

Fraction decomposition [src]

(2 + a)/(3*(4 + a^2 + 2*a))

$$\frac{a + 2}{3 \left(a^{2} + 2 a + 4\right)}$$

     2 + a      
----------------
  /     2      \
3*\4 + a  + 2*a/

General simplification [src]

        2  
  -4 + a   
-----------
  /      3\
3*\-8 + a /

$$\frac{a^{2} - 4}{3 \left(a^{3} - 8\right)}$$

(-4 + a^2)/(3*(-8 + a^3))

Numerical answer [src]

(-12.0 + 3.0*a^2)/(-72.0 + 9.0*a^3)

(-12.0 + 3.0*a^2)/(-72.0 + 9.0*a^3)

Common denominator [src]

     2 + a     
---------------
        2      
12 + 3*a  + 6*a

$$\frac{a + 2}{3 a^{2} + 6 a + 12}$$

(2 + a)/(12 + 3*a^2 + 6*a)

Combining rational expressions [src]

        2  
  -4 + a   
-----------
  /      3\
3*\-8 + a /

$$\frac{a^{2} - 4}{3 \left(a^{3} - 8\right)}$$

(-4 + a^2)/(3*(-8 + a^3))

Combinatorics [src]

     2 + a      
----------------
  /     2      \
3*\4 + a  + 2*a/

$$\frac{a + 2}{3 \left(a^{2} + 2 a + 4\right)}$$

(2 + a)/(3*(4 + a^2 + 2*a))