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Limit of the function x^2-y

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     / 2    \
 lim \x  - y/
x->oo        
limx(x2y)\lim_{x \to \infty}\left(x^{2} - y\right)
Limit(x^2 - y, x, oo, dir='-')
Detail solution
Let's take the limit
limx(x2y)\lim_{x \to \infty}\left(x^{2} - y\right)
Let's divide numerator and denominator by x^2:
limx(x2y)\lim_{x \to \infty}\left(x^{2} - y\right) =
limx(1yx21x2)\lim_{x \to \infty}\left(\frac{1 - \frac{y}{x^{2}}}{\frac{1}{x^{2}}}\right)
Do Replacement
u=1xu = \frac{1}{x}
then
limx(1yx21x2)=limu0+(u2y+1u2)\lim_{x \to \infty}\left(\frac{1 - \frac{y}{x^{2}}}{\frac{1}{x^{2}}}\right) = \lim_{u \to 0^+}\left(\frac{- u^{2} y + 1}{u^{2}}\right)
=
02y+10=\frac{- 0^{2} y + 1}{0} = \infty

The final answer:
limx(x2y)=\lim_{x \to \infty}\left(x^{2} - y\right) = \infty
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
Rapid solution [src]
oo
\infty
Other limits x→0, -oo, +oo, 1
limx(x2y)=\lim_{x \to \infty}\left(x^{2} - y\right) = \infty
limx0(x2y)=y\lim_{x \to 0^-}\left(x^{2} - y\right) = - y
More at x→0 from the left
limx0+(x2y)=y\lim_{x \to 0^+}\left(x^{2} - y\right) = - y
More at x→0 from the right
limx1(x2y)=y+1\lim_{x \to 1^-}\left(x^{2} - y\right) = - y + 1
More at x→1 from the left
limx1+(x2y)=y+1\lim_{x \to 1^+}\left(x^{2} - y\right) = - y + 1
More at x→1 from the right
limx(x2y)=\lim_{x \to -\infty}\left(x^{2} - y\right) = \infty
More at x→-oo