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Integral of x^2-y dy

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The solution

You have entered [src]
    3           
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02x3(x2y)dy\int\limits_{0}^{2 x^{3}} \left(x^{2} - y\right)\, dy
Integral(x^2 - y, (y, 0, 2*x^3))
Detail solution
  1. Integrate term-by-term:

    1. The integral of a constant is the constant times the variable of integration:

      x2dy=x2y\int x^{2}\, dy = x^{2} y

    1. The integral of a constant times a function is the constant times the integral of the function:

      (y)dy=ydy\int \left(- y\right)\, dy = - \int y\, dy

      1. The integral of yny^{n} is yn+1n+1\frac{y^{n + 1}}{n + 1} when n1n \neq -1:

        ydy=y22\int y\, dy = \frac{y^{2}}{2}

      So, the result is: y22- \frac{y^{2}}{2}

    The result is: x2yy22x^{2} y - \frac{y^{2}}{2}

  2. Now simplify:

    y(2x2y)2\frac{y \left(2 x^{2} - y\right)}{2}

  3. Add the constant of integration:

    y(2x2y)2+constant\frac{y \left(2 x^{2} - y\right)}{2}+ \mathrm{constant}


The answer is:

y(2x2y)2+constant\frac{y \left(2 x^{2} - y\right)}{2}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                           
 |                    2       
 | / 2    \          y       2
 | \x  - y/ dy = C - -- + y*x 
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(x2y)dy=C+x2yy22\int \left(x^{2} - y\right)\, dy = C + x^{2} y - \frac{y^{2}}{2}
The answer [src]
     6      5
- 2*x  + 2*x 
2x6+2x5- 2 x^{6} + 2 x^{5}
=
=
     6      5
- 2*x  + 2*x 
2x6+2x5- 2 x^{6} + 2 x^{5}
-2*x^6 + 2*x^5

    Use the examples entering the upper and lower limits of integration.