Mister Exam

Integral of tan5x dx

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The solution

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01tan(5x)dx\int\limits_{0}^{1} \tan{\left(5 x \right)}\, dx
Integral(tan(5*x), (x, 0, 1))
Detail solution
  1. Rewrite the integrand:

    tan(5x)=sin(5x)cos(5x)\tan{\left(5 x \right)} = \frac{\sin{\left(5 x \right)}}{\cos{\left(5 x \right)}}

  2. There are multiple ways to do this integral.

    Method #1

    1. Let u=cos(5x)u = \cos{\left(5 x \right)}.

      Then let du=5sin(5x)dxdu = - 5 \sin{\left(5 x \right)} dx and substitute du5- \frac{du}{5}:

      (15u)du\int \left(- \frac{1}{5 u}\right)\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        1udu=1udu5\int \frac{1}{u}\, du = - \frac{\int \frac{1}{u}\, du}{5}

        1. The integral of 1u\frac{1}{u} is log(u)\log{\left(u \right)}.

        So, the result is: log(u)5- \frac{\log{\left(u \right)}}{5}

      Now substitute uu back in:

      log(cos(5x))5- \frac{\log{\left(\cos{\left(5 x \right)} \right)}}{5}

    Method #2

    1. Let u=5xu = 5 x.

      Then let du=5dxdu = 5 dx and substitute du5\frac{du}{5}:

      sin(u)5cos(u)du\int \frac{\sin{\left(u \right)}}{5 \cos{\left(u \right)}}\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        sin(u)cos(u)du=sin(u)cos(u)du5\int \frac{\sin{\left(u \right)}}{\cos{\left(u \right)}}\, du = \frac{\int \frac{\sin{\left(u \right)}}{\cos{\left(u \right)}}\, du}{5}

        1. Let u=cos(u)u = \cos{\left(u \right)}.

          Then let du=sin(u)dudu = - \sin{\left(u \right)} du and substitute du- du:

          (1u)du\int \left(- \frac{1}{u}\right)\, du

          1. The integral of a constant times a function is the constant times the integral of the function:

            1udu=1udu\int \frac{1}{u}\, du = - \int \frac{1}{u}\, du

            1. The integral of 1u\frac{1}{u} is log(u)\log{\left(u \right)}.

            So, the result is: log(u)- \log{\left(u \right)}

          Now substitute uu back in:

          log(cos(u))- \log{\left(\cos{\left(u \right)} \right)}

        So, the result is: log(cos(u))5- \frac{\log{\left(\cos{\left(u \right)} \right)}}{5}

      Now substitute uu back in:

      log(cos(5x))5- \frac{\log{\left(\cos{\left(5 x \right)} \right)}}{5}

  3. Add the constant of integration:

    log(cos(5x))5+constant- \frac{\log{\left(\cos{\left(5 x \right)} \right)}}{5}+ \mathrm{constant}


The answer is:

log(cos(5x))5+constant- \frac{\log{\left(\cos{\left(5 x \right)} \right)}}{5}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                               
 |                   log(cos(5*x))
 | tan(5*x) dx = C - -------------
 |                         5      
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tan(5x)dx=Clog(cos(5x))5\int \tan{\left(5 x \right)}\, dx = C - \frac{\log{\left(\cos{\left(5 x \right)} \right)}}{5}
The graph
0.001.000.100.200.300.400.500.600.700.800.90-2000010000
Numerical answer [src]
1.33441279257591
1.33441279257591
The graph
Integral of tan5x dx

    Use the examples entering the upper and lower limits of integration.