Integral of sqrt(x+4) dx
The solution
Detail solution
-
Let u=x+4.
Then let du=dx and substitute du:
∫udu
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The integral of un is n+1un+1 when n=−1:
∫udu=32u23
Now substitute u back in:
32(x+4)23
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Now simplify:
32(x+4)23
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Add the constant of integration:
32(x+4)23+constant
The answer is:
32(x+4)23+constant
The answer (Indefinite)
[src]
/
| 3/2
| _______ 2*(x + 4)
| \/ x + 4 dx = C + ------------
| 3
/
∫x+4dx=C+32(x+4)23
The graph
___
16 10*\/ 5
- -- + --------
3 3
−316+3105
=
___
16 10*\/ 5
- -- + --------
3 3
−316+3105
Use the examples entering the upper and lower limits of integration.