Integral of (3/sqrt(x))+4/(x^8) dx
The solution
Detail solution
-
Integrate term-by-term:
-
The integral of a constant times a function is the constant times the integral of the function:
∫x84dx=4∫x81dx
-
Don't know the steps in finding this integral.
But the integral is
−7x71
So, the result is: −7x74
-
The integral of a constant times a function is the constant times the integral of the function:
∫x3dx=3∫x1dx
-
Let u=x.
Then let du=2xdx and substitute 2du:
-
The integral of a constant times a function is the constant times the integral of the function:
-
The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: 2u
Now substitute u back in:
So, the result is: 6x
The result is: 6x−7x74
-
Now simplify:
7x72(21x215−2)
-
Add the constant of integration:
7x72(21x215−2)+constant
The answer is:
7x72(21x215−2)+constant
The answer (Indefinite)
[src]
/
|
| / 3 4 \ ___ 4
| |----- + --| dx = C + 6*\/ x - ----
| | ___ 8| 7
| \\/ x x / 7*x
|
/
∫(x84+x3)dx=C+6x−7x74
The graph
Use the examples entering the upper and lower limits of integration.