1 / | | 1 | ----- dx | x + y | / 0
Integral(1/(x + y), (x, 0, 1))
Let .
Then let and substitute :
The integral of is .
Now substitute back in:
Add the constant of integration:
The answer is:
/ | | 1 | ----- dx = C + log(x + y) | x + y | /
-log(y) + log(1 + y)
=
-log(y) + log(1 + y)
-log(y) + log(1 + y)
Use the examples entering the upper and lower limits of integration.