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Integral of 1/(x+y) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1         
  /         
 |          
 |    1     
 |  ----- dx
 |  x + y   
 |          
/           
0           
$$\int\limits_{0}^{1} \frac{1}{x + y}\, dx$$
Integral(1/(x + y), (x, 0, 1))
Detail solution
  1. Let .

    Then let and substitute :

    1. The integral of is .

    Now substitute back in:

  2. Add the constant of integration:


The answer is:

The answer (Indefinite) [src]
  /                         
 |                          
 |   1                      
 | ----- dx = C + log(x + y)
 | x + y                    
 |                          
/                           
$$\int \frac{1}{x + y}\, dx = C + \log{\left(x + y \right)}$$
The answer [src]
-log(y) + log(1 + y)
$$- \log{\left(y \right)} + \log{\left(y + 1 \right)}$$
=
=
-log(y) + log(1 + y)
$$- \log{\left(y \right)} + \log{\left(y + 1 \right)}$$
-log(y) + log(1 + y)

    Use the examples entering the upper and lower limits of integration.