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Integral of (1/x)+y*exp(x) dx

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The solution

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01(yex+1x)dx\int\limits_{0}^{1} \left(y e^{x} + \frac{1}{x}\right)\, dx
Integral(1/x + y*exp(x), (x, 0, 1))
Detail solution
  1. Integrate term-by-term:

    1. The integral of a constant times a function is the constant times the integral of the function:

      yexdx=yexdx\int y e^{x}\, dx = y \int e^{x}\, dx

      1. The integral of the exponential function is itself.

        exdx=ex\int e^{x}\, dx = e^{x}

      So, the result is: yexy e^{x}

    1. The integral of 1x\frac{1}{x} is log(x)\log{\left(x \right)}.

    The result is: yex+log(x)y e^{x} + \log{\left(x \right)}

  2. Add the constant of integration:

    yex+log(x)+constanty e^{x} + \log{\left(x \right)}+ \mathrm{constant}


The answer is:

yex+log(x)+constanty e^{x} + \log{\left(x \right)}+ \mathrm{constant}

The answer (Indefinite) [src]
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(yex+1x)dx=C+yex+log(x)\int \left(y e^{x} + \frac{1}{x}\right)\, dx = C + y e^{x} + \log{\left(x \right)}
The answer [src]
oo + E*y
ey+e y + \infty
=
=
oo + E*y
ey+e y + \infty
oo + E*y

    Use the examples entering the upper and lower limits of integration.