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Solving integrals/ 1/sqrt(3x+4)

Integral of 1/sqrt(3x+4) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src] 
 -1               
  /               
 |                
 |       1        
 |  ----------- dx
 |    _________   
 |  \/ 3*x + 4    
 |                
/                 
7
∫7−113x+4 dx\int\limits_{7}^{-1} \frac{1}{\sqrt{3 x + 4}}\, dx 
Integral(1/(sqrt(3*x + 4)), (x, 7, -1))
Detail solution

  1. Let u=3x+4u = \sqrt{3 x + 4}.

    Then let du=3dx23x+4du = \frac{3 dx}{2 \sqrt{3 x + 4}} and substitute 2du3\frac{2 du}{3}:

    ∫23 du\int \frac{2}{3}\, du

    1. The integral of a constant times a function is the constant times the integral of the function:

      False\text{False}

      1. The integral of a constant is the constant times the variable of integration:

        ∫1 du=u\int 1\, du = u

      So, the result is: 2u3\frac{2 u}{3}

    Now substitute uu back in:

    23x+43\frac{2 \sqrt{3 x + 4}}{3}

  2. Now simplify:

    23x+43\frac{2 \sqrt{3 x + 4}}{3}

  3. Add the constant of integration:

    23x+43+constant\frac{2 \sqrt{3 x + 4}}{3}+ \mathrm{constant}

The answer is:

23x+43+constant\frac{2 \sqrt{3 x + 4}}{3}+ \mathrm{constant}

The answer (Indefinite) [src] 
  /                                  
 |                          _________
 |      1               2*\/ 3*x + 4 
 | ----------- dx = C + -------------
 |   _________                3      
 | \/ 3*x + 4                        
 |                                   
/
∫13x+4 dx=C+23x+43\int \frac{1}{\sqrt{3 x + 4}}\, dx = C + \frac{2 \sqrt{3 x + 4}}{3}
Simplify
The graph
7.00.01.02.03.04.05.06.0-1.005
Plot the graph f(x)
The answer [src] 
-8/3
−83- \frac{8}{3} 
=
= 
-8/3
−83- \frac{8}{3} 
-8/3
Numerical answer [src] 
-2.66666666666667
-2.66666666666667

    Use the examples entering the upper and lower limits of integration.

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