Integral of -x^2-4x-3 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2)dx=−∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: −3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−4x)dx=−4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
The result is: −3x3−2x2
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The integral of a constant is the constant times the variable of integration:
∫(−3)dx=−3x
The result is: −3x3−2x2−3x
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Now simplify:
−3x(x2+6x+9)
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Add the constant of integration:
−3x(x2+6x+9)+constant
The answer is:
−3x(x2+6x+9)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ 2 x
| \- x - 4*x - 3/ dx = C - 3*x - 2*x - --
| 3
/
∫((−x2−4x)−3)dx=C−3x3−2x2−3x
The graph
Use the examples entering the upper and lower limits of integration.