Integral of -x^2+4x-3 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2)dx=−∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: −3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫4xdx=4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 2x2
The result is: −3x3+2x2
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The integral of a constant is the constant times the variable of integration:
∫(−3)dx=−3x
The result is: −3x3+2x2−3x
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Now simplify:
3x(−x2+6x−9)
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Add the constant of integration:
3x(−x2+6x−9)+constant
The answer is:
3x(−x2+6x−9)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ 2 x
| \- x + 4*x - 3/ dx = C - 3*x + 2*x - --
| 3
/
∫((−x2+4x)−3)dx=C−3x3+2x2−3x
The graph
Use the examples entering the upper and lower limits of integration.