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-x^2+4x-3

Integral of -x^2+4x-3 dx

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13((x2+4x)3)dx\int\limits_{1}^{3} \left(\left(- x^{2} + 4 x\right) - 3\right)\, dx
Integral(-x^2 + 4*x - 3, (x, 1, 3))
Detail solution
  1. Integrate term-by-term:

    1. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

        (x2)dx=x2dx\int \left(- x^{2}\right)\, dx = - \int x^{2}\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

          x2dx=x33\int x^{2}\, dx = \frac{x^{3}}{3}

        So, the result is: x33- \frac{x^{3}}{3}

      1. The integral of a constant times a function is the constant times the integral of the function:

        4xdx=4xdx\int 4 x\, dx = 4 \int x\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

          xdx=x22\int x\, dx = \frac{x^{2}}{2}

        So, the result is: 2x22 x^{2}

      The result is: x33+2x2- \frac{x^{3}}{3} + 2 x^{2}

    1. The integral of a constant is the constant times the variable of integration:

      (3)dx=3x\int \left(-3\right)\, dx = - 3 x

    The result is: x33+2x23x- \frac{x^{3}}{3} + 2 x^{2} - 3 x

  2. Now simplify:

    x(x2+6x9)3\frac{x \left(- x^{2} + 6 x - 9\right)}{3}

  3. Add the constant of integration:

    x(x2+6x9)3+constant\frac{x \left(- x^{2} + 6 x - 9\right)}{3}+ \mathrm{constant}


The answer is:

x(x2+6x9)3+constant\frac{x \left(- x^{2} + 6 x - 9\right)}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                         
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 | \- x  + 4*x - 3/ dx = C - 3*x + 2*x  - --
 |                                        3 
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((x2+4x)3)dx=Cx33+2x23x\int \left(\left(- x^{2} + 4 x\right) - 3\right)\, dx = C - \frac{x^{3}}{3} + 2 x^{2} - 3 x
The graph
1.03.01.21.41.61.82.02.22.42.62.82.5-2.5
The answer [src]
4/3
43\frac{4}{3}
=
=
4/3
43\frac{4}{3}
4/3
Numerical answer [src]
1.33333333333333
1.33333333333333
The graph
Integral of -x^2+4x-3 dx

    Use the examples entering the upper and lower limits of integration.