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Integral of cos(3x+5) dx

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The solution

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 |  cos(3*x + 5) dx
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00cos(3x+5)dx\int\limits_{0}^{0} \cos{\left(3 x + 5 \right)}\, dx
Integral(cos(3*x + 5), (x, 0, 0))
Detail solution
  1. Let u=3x+5u = 3 x + 5.

    Then let du=3dxdu = 3 dx and substitute du3\frac{du}{3}:

    cos(u)3du\int \frac{\cos{\left(u \right)}}{3}\, du

    1. The integral of a constant times a function is the constant times the integral of the function:

      cos(u)du=cos(u)du3\int \cos{\left(u \right)}\, du = \frac{\int \cos{\left(u \right)}\, du}{3}

      1. The integral of cosine is sine:

        cos(u)du=sin(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}

      So, the result is: sin(u)3\frac{\sin{\left(u \right)}}{3}

    Now substitute uu back in:

    sin(3x+5)3\frac{\sin{\left(3 x + 5 \right)}}{3}

  2. Now simplify:

    sin(3x+5)3\frac{\sin{\left(3 x + 5 \right)}}{3}

  3. Add the constant of integration:

    sin(3x+5)3+constant\frac{\sin{\left(3 x + 5 \right)}}{3}+ \mathrm{constant}


The answer is:

sin(3x+5)3+constant\frac{\sin{\left(3 x + 5 \right)}}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                  
 |                       sin(3*x + 5)
 | cos(3*x + 5) dx = C + ------------
 |                            3      
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cos(3x+5)dx=C+sin(3x+5)3\int \cos{\left(3 x + 5 \right)}\, dx = C + \frac{\sin{\left(3 x + 5 \right)}}{3}
The graph
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    Use the examples entering the upper and lower limits of integration.