Mister Exam

Integral of cos3x+5dx dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1                  
  /                  
 |                   
 |  (cos(3*x) + 5) dx
 |                   
/                    
0                    
01(cos(3x)+5)dx\int\limits_{0}^{1} \left(\cos{\left(3 x \right)} + 5\right)\, dx
Integral(cos(3*x) + 5, (x, 0, 1))
Detail solution
  1. Integrate term-by-term:

    1. Let u=3xu = 3 x.

      Then let du=3dxdu = 3 dx and substitute du3\frac{du}{3}:

      cos(u)3du\int \frac{\cos{\left(u \right)}}{3}\, du

      1. The integral of a constant times a function is the constant times the integral of the function:

        cos(u)du=cos(u)du3\int \cos{\left(u \right)}\, du = \frac{\int \cos{\left(u \right)}\, du}{3}

        1. The integral of cosine is sine:

          cos(u)du=sin(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}

        So, the result is: sin(u)3\frac{\sin{\left(u \right)}}{3}

      Now substitute uu back in:

      sin(3x)3\frac{\sin{\left(3 x \right)}}{3}

    1. The integral of a constant is the constant times the variable of integration:

      5dx=5x\int 5\, dx = 5 x

    The result is: 5x+sin(3x)35 x + \frac{\sin{\left(3 x \right)}}{3}

  2. Add the constant of integration:

    5x+sin(3x)3+constant5 x + \frac{\sin{\left(3 x \right)}}{3}+ \mathrm{constant}


The answer is:

5x+sin(3x)3+constant5 x + \frac{\sin{\left(3 x \right)}}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                      
 |                               sin(3*x)
 | (cos(3*x) + 5) dx = C + 5*x + --------
 |                                  3    
/                                        
(cos(3x)+5)dx=C+5x+sin(3x)3\int \left(\cos{\left(3 x \right)} + 5\right)\, dx = C + 5 x + \frac{\sin{\left(3 x \right)}}{3}
The graph
0.001.000.100.200.300.400.500.600.700.800.90010
The answer [src]
    sin(3)
5 + ------
      3   
sin(3)3+5\frac{\sin{\left(3 \right)}}{3} + 5
=
=
    sin(3)
5 + ------
      3   
sin(3)3+5\frac{\sin{\left(3 \right)}}{3} + 5
5 + sin(3)/3
Numerical answer [src]
5.04704000268662
5.04704000268662

    Use the examples entering the upper and lower limits of integration.