Mister Exam
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How to use it?
- Express {x} in terms of y where:
- -16*x+7*y=-5
- -2*x-1*y=-8
- -4*x-18*y=-14
- 1*x-4*y=1
- Equation:
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Equation (7x+1)-(9x+3)=5
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Equation sin(x^2)=0
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Equation (x+2)^2+(x-3)^2=2x^2
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Equation 9-7(x+3)=5-6x
- Limit of the function:
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-5
- -5
- Derivative of:
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-5
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Identical expressions
- - sixteen *x+ seven *y=- five
- minus 16 multiply by x plus 7 multiply by y equally minus 5
- minus sixteen multiply by x plus seven multiply by y equally minus five
- -16x+7y=-5
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Similar expressions
- -16*x+7*y=+5
- 16*x+7*y=-5
- -16*x-7*y=-5
Express x in terms of y where -16*x+7*y=-5
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = - 7 y - 5$$
Divide both parts of the equation by -16
We get the answer: x = 5/16 + 7*y/16
-16*x+7*y = -5
Looking for similar summands in the left part:
-16*x + 7*y = -5
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = - 7 y - 5$$
Divide both parts of the equation by -16
x = -5 - 7*y / (-16)
We get the answer: x = 5/16 + 7*y/16
Rapid solution
[src]
5 7*re(y) 7*I*im(y)
x1 = -- + ------- + ---------
16 16 16
$$x_{1} = \frac{7 \operatorname{re}{\left(y\right)}}{16} + \frac{7 i \operatorname{im}{\left(y\right)}}{16} + \frac{5}{16}$$
x1 = 7*re(y)/16 + 7*i*im(y)/16 + 5/16