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How to use it?
- Equation:
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Equation (7x+1)-(9x+3)=5
-
Equation (x+2)^2+(x-3)^2=2x^2
-
Equation 9-7(x+3)=5-6x
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Equation cosx=1
- Express {x} in terms of y where:
- -16*x+7*y=-5
- -2*x-1*y=-8
- -4*x-18*y=-14
- 1*x-4*y=1
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Identical expressions
- (7x+ one)-(9x+ three)= five
- (7x plus 1) minus (9x plus 3) equally 5
- (7x plus one) minus (9x plus three) equally five
- 7x+1-9x+3=5
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Similar expressions
- (7x+1)-(9x-3)=5
- (7*x+1)-(9*x+3)=5
- (7x+1)+(9x+3)=5
- (7x-1)-(9x+3)=5
(7x+1)-(9x+3)=5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7$$
Divide both parts of the equation by -2
We get the answer: x = -7/2
(7*x+1)-(9*x+3) = 5
Expand brackets in the left part
7*x+1-9*x-3 = 5
Looking for similar summands in the left part:
-2 - 2*x = 5
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 7$$
Divide both parts of the equation by -2
x = 7 / (-2)
We get the answer: x = -7/2
Sum and product of roots
[src]
sum
-7/2
$$- \frac{7}{2}$$
=
-7/2
$$- \frac{7}{2}$$
product
-7/2
$$- \frac{7}{2}$$
=
-7/2
$$- \frac{7}{2}$$
-7/2
The graph