Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (7x+1)-(9x+3)=5
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Equation (x+2)^2+(x-3)^2=2x^2
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Equation 9-7(x+3)=5-6x
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Equation cosx=1
- Express {x} in terms of y where:
- -16*x+7*y=-5
- -2*x-1*y=-8
- -4*x-18*y=-14
- 1*x-4*y=1
- Integral of d{x}:
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2x^2
- Derivative of:
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2x^2
- Canonical form:
- 2x^2
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Identical expressions
- (x+ two)^ two +(x- three)^ two = two x^2
- (x plus 2) squared plus (x minus 3) squared equally 2x squared
- (x plus two) to the power of two plus (x minus three) to the power of two equally two x squared
- (x+2)2+(x-3)2=2x2
- x+22+x-32=2x2
- (x+2)²+(x-3)²=2x²
- (x+2) to the power of 2+(x-3) to the power of 2=2x to the power of 2
- x+2^2+x-3^2=2x^2
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Similar expressions
- sqrt(5x^2-20x+21)+sqrt(3x^2-12x+28)=8x-2x^2-3
- (x+2)^2-(x-3)^2=2x^2
- lg^2(x^2)+lg(10*x)-6=0
- (x-2)^2+(x-3)^2=2x^2
- (x+2)^2+(x+3)^2=2x^2
- -2*x+4*x+5=2*x^2-7*x+2*x-3
- (sqrt(x)-3)*(2*x^2+3*x-5)=0
(x+2)^2+(x-3)^2=2x^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 2 (x + 2) + (x - 3) = 2*x
$$\left(x - 3\right)^{2} + \left(x + 2\right)^{2} = 2 x^{2}$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = -13$$
Divide both parts of the equation by -2
We get the answer: x = 13/2
(x+2)^2+(x-3)^2 = 2*x^2
Expand expressions:
4 + x^2 + 4*x + (x - 3)^2 = 2*x^2
4 + x^2 + 4*x + 9 + x^2 - 6*x = 2*x^2
Reducing, you get:
13 - 2*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = -13$$
Divide both parts of the equation by -2
x = -13 / (-2)
We get the answer: x = 13/2
Sum and product of roots
[src]
sum
13/2
$$\frac{13}{2}$$
=
13/2
$$\frac{13}{2}$$
product
13/2
$$\frac{13}{2}$$
=
13/2
$$\frac{13}{2}$$
13/2
The graph