Mister Exam
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How to use it?
- Equation:
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Equation sin(x)=1
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Equation (7x+1)-(9x+3)=5
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Equation sin(x^2)=0
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Equation (x+2)^2+(x-3)^2=2x^2
- Express {x} in terms of y where:
- -16*x+7*y=-5
- -2*x-1*y=-8
- -4*x-18*y=-14
- 1*x-4*y=1
- Graphing y =:
- 5-6x
- Derivative of:
- 5-6x
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Identical expressions
- nine - seven (x+ three)= five -6x
- 9 minus 7(x plus 3) equally 5 minus 6x
- nine minus seven (x plus three) equally five minus 6x
- 9-7x+3=5-6x
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Similar expressions
- 9-7(x-3)=5-6x
- (9x-4)/5-(6x-1)/7=5
- 9-7(x+3)=5+6x
- (0,5-6*x)(0,25+3x+36x^2)=0,125
- 9-7*(x+3)=5-6*x
- 9+7(x+3)=5-6x
9-7(x+3)=5-6x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 17 - 6 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
We get the answer: x = -17
9-7*(x+3) = 5-6*x
Expand brackets in the left part
9-7*x-7*3 = 5-6*x
Looking for similar summands in the left part:
-12 - 7*x = 5-6*x
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = 17 - 6 x$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
x = 17 / (-1)
We get the answer: x = -17
The graph