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- Equation:
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Equation (x-2)^2+(x-3)^2=2x^2
-
Equation 3x^2-27=0
-
Equation sin(x+pi/3)=0
-
Equation sin(x)=-√3/2
- Express {x} in terms of y where:
- -6*x-2*y=-10
- 18*x+14*y=-11
- 4*x+16*y=6
- sin(xy)+cos(xy)=tg(x+y)
- Integral of d{x}:
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2x^2
- Derivative of:
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2x^2
- Canonical form:
- 2x^2
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Identical expressions
- (x- two)^ two +(x- three)^ two = two x^2
- (x minus 2) squared plus (x minus 3) squared equally 2x squared
- (x minus two) to the power of two plus (x minus three) to the power of two equally two x squared
- (x-2)2+(x-3)2=2x2
- x-22+x-32=2x2
- (x-2)²+(x-3)²=2x²
- (x-2) to the power of 2+(x-3) to the power of 2=2x to the power of 2
- x-2^2+x-3^2=2x^2
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Similar expressions
- (sqrt(x)-3)*(2*x^2+3*x-5)=0
- -2*x+4*x+5=2*x^2-7*x+2*x-3
- (x+2)^2+(x-3)^2=2x^2
- lg^2(x^2)+lg(10*x)-6=0
- (x-2)^2+(x+3)^2=2x^2
- (x-2)^2-(x-3)^2=2x^2
(x-2)^2+(x-3)^2=2x^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 2 (x - 2) + (x - 3) = 2*x
$$\left(x - 2\right)^{2} + \left(x - 3\right)^{2} = 2 x^{2}$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = -13$$
Divide both parts of the equation by -10
We get the answer: x = 13/10
(x-2)^2+(x-3)^2 = 2*x^2
Expand expressions:
4 + x^2 - 4*x + (x - 1*3)^2 = 2*x^2
4 + x^2 - 4*x + 9 + x^2 - 6*x = 2*x^2
Reducing, you get:
13 - 10*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 10 x = -13$$
Divide both parts of the equation by -10
x = -13 / (-10)
We get the answer: x = 13/10
Sum and product of roots
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sum
13
0 + --
10
$$0 + \frac{13}{10}$$
=
13 -- 10
$$\frac{13}{10}$$
product
13 1*-- 10
$$1 \cdot \frac{13}{10}$$
=
13 -- 10
$$\frac{13}{10}$$
13/10
The graph