Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation x-y=1
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Equation 4-6*(x+2)=3-5*x
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Equation 4-6(x+2)=3-5x
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Equation 1/(x-3)^2-3/(x-3)-4=0
- Express {x} in terms of y where:
- 18*x-8*y=-2
- -11*x+15*y=7
- 6*x+17*y=3
- 4*x+2*y=5
- Expression:
- x-y
- x-y
- Limit of the function:
- x-y
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Identical expressions
- x-y= one
- x minus y equally 1
- x minus y equally one
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Similar expressions
- 2^(x^(-y))-10*|x-3*y|=236
- x+y=1
x-y=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$x = y + 1$$
We get the answer: x = 1 + y
x-y = 1
Looking for similar summands in the left part:
x - y = 1
Move the summands with the other variables
from left part to right part, we given:
$$x = y + 1$$
We get the answer: x = 1 + y
The graph
Rapid solution
[src]
x1 = 1 + I*im(y) + re(y)
$$x_{1} = \operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
x1 = re(y) + i*im(y) + 1
Sum and product of roots
[src]
sum
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
=
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
product
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
=
1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 1$$
1 + i*im(y) + re(y)