Mister Exam
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How to use it?
- Equation:
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Equation 1-5*x=-6*x+8
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Equation 8*x-3*(2*x+1)=2*x+4
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Equation 3^x+4^x=5^x
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Equation x^4=(3*x-4)^2
- Express {x} in terms of y where:
- 7*x+19*y=12
- -9*x-4*y=-20
- 12*x-14*y=20
- -18*x+8*y=-2
- Derivative of:
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1-5*x
- Integral of d{x}:
- 1-5*x
- Limit of the function:
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1-5*x
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Identical expressions
- one - five *x=- six *x+ eight
- 1 minus 5 multiply by x equally minus 6 multiply by x plus 8
- one minus five multiply by x equally minus six multiply by x plus eight
- 1-5x=-6x+8
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Similar expressions
- (x^2-7*x-11)-(5*x^2-13*x-18)=16-4*x^2
- 1+5*x=-6*x+8
- 4(1-5x)=9-3(6x-5)
- (5/(x-2))+(2/(x-4))=11/((x^2)-(6*x)+8)
- 8x^2+(-16x-5)x+11-5x-7=0
- 1-5*x=-6*x-8
- (x^2-6x+8)^2-9x^2-6x=1
- 1-5*x=+6*x+8
- 5^(x-1)-5^(x-3)=24/25
1-5*x=-6*x+8 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 7 - 6 x$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 7$$
We get the answer: x = 7
1-5*x = -6*x+8
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 7 - 6 x$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 7$$
We get the answer: x = 7
The graph