Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+2)^4-4*(x+2)^2-5=0
- Equation x-y=2
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Equation x^3+2x^2-x-2=0
- Equation (x+20)*(-x+10)=0
- Express {x} in terms of y where:
- 15*x+7*y=2
- 12*x-20*y=10
- -17*x-15*y=-17
- 6*x-2*y=20
- Canonical form:
- x+y
- x+y
- Limit of the function:
- x+y
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Identical expressions
- x+y= one
- x plus y equally 1
- x plus y equally one
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Similar expressions
- x-y=1
x+y=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$x = 1 - y$$
We get the answer: x = 1 - y
x+y = 1
Looking for similar summands in the left part:
x + y = 1
Move the summands with the other variables
from left part to right part, we given:
$$x = 1 - y$$
We get the answer: x = 1 - y
The graph
Sum and product of roots
[src]
sum
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
=
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
product
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
=
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
1 - re(y) - i*im(y)
Rapid solution
[src]
x1 = 1 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
x1 = -re(y) - i*im(y) + 1