Mister Exam
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How to use it?
- Express {x} in terms of y where:
- 2*x+2*y=-6
- 7*x+20*y=-17
- 12*x+14*y=-15
- -11*x+10*y=-9
- Equation:
-
Equation e^x=0
-
Equation x^2=10
-
Equation cos(x)=3
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Equation x^2-3x-4=0
- Integral of d{x}:
- -9
- Limit of the function:
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-9
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Identical expressions
- - eleven *x+ ten *y=- nine
- minus 11 multiply by x plus 10 multiply by y equally minus 9
- minus eleven multiply by x plus ten multiply by y equally minus nine
- -11x+10y=-9
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Similar expressions
- -11*x-10*y=-9
- 11*x+10*y=-9
- -11*x+10*y=+9
Express x in terms of y where -11*x+10*y=-9
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 11 x = - 10 y - 9$$
Divide both parts of the equation by -11
We get the answer: x = 9/11 + 10*y/11
-11*x+10*y = -9
Looking for similar summands in the left part:
-11*x + 10*y = -9
Move the summands with the other variables
from left part to right part, we given:
$$- 11 x = - 10 y - 9$$
Divide both parts of the equation by -11
x = -9 - 10*y / (-11)
We get the answer: x = 9/11 + 10*y/11
Rapid solution
[src]
9 10*re(y) 10*I*im(y)
x1 = -- + -------- + ----------
11 11 11
$$x_{1} = \frac{10 \operatorname{re}{\left(y\right)}}{11} + \frac{10 i \operatorname{im}{\left(y\right)}}{11} + \frac{9}{11}$$
x1 = 10*re(y)/11 + 10*i*im(y)/11 + 9/11