Mister Exam
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How to use it?
- Equation:
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Equation tan(x)=0
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Equation log(4/(7-x))/log(x^2)=5
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Equation x-2(3x+2)=16
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Equation (7x+1)-(9x+3)=5
- Express {x} in terms of y where:
- (x^2+y^2-1)^3-x^2*y^3=0
- -2*x+1*y=-8
- -2*x-1*y=-8
- 4*x+15*y=19
- Sum of series:
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16
- Derivative of:
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16
- Integral of d{x}:
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16
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Identical expressions
- x- two (3x+ two)= sixteen
- x minus 2(3x plus 2) equally 16
- x minus two (3x plus two) equally sixteen
- x-23x+2=16
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Similar expressions
- x+2(3x+2)=16
- (3x-2)*(3x+2)+(4x-5)^2=10x+21
- x-2*(3x+2)=16
- (3*x-2)*(3*x+2)+(4*x-5)^2=10*x+21
- (3x-2)(3x+2)-(3x-1)(3x+3)=5.
- x-2(3x-2)=16
x-2(3x+2)=16 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 20$$
Divide both parts of the equation by -5
We get the answer: x = -4
x-2*(3*x+2) = 16
Expand brackets in the left part
x-2*3*x-2*2 = 16
Looking for similar summands in the left part:
-4 - 5*x = 16
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 20$$
Divide both parts of the equation by -5
x = 20 / (-5)
We get the answer: x = -4
The graph