x-2*(3x+2)=16 equation

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You have entered [src]

x - 2*(3*x + 2) = 16

$$x - 2 \left(3 x + 2\right) = 16$$

Simplify

Detail solution

Given the linear equation:

x-2*(3*x+2) = 16

Expand brackets in the left part

x-2*3*x-2*2 = 16

Looking for similar summands in the left part:

-4 - 5*x = 16

Move free summands (without x)
from left part to right part, we given:
$$- 5 x = 20$$
Divide both parts of the equation by -5

x = 20 / (-5)

We get the answer: x = -4

The graph

Plot the graph f1(x)

Plot the graph f2(x)

Rapid solution [src]

x1 = -4

$$x_{1} = -4$$

x1 = -4

Sum and product of roots [src]

sum

-4

$$-4$$

-4

$$-4$$

product

-4

$$-4$$

-4

$$-4$$

-4

Numerical answer [src]

x1 = -4.0

x1 = -4.0