Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+x-20=0
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Equation log(27)*x=1/3
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Equation 5x^2=-80+40x
- Equation x^2-289=0
- Express {x} in terms of y where:
- 15*x-17*y=19
- 9*x-8*y=6
- 15*x+15*y=16
- 8*x+7*y=-13
- Derivative of:
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1/3
- Sum of series:
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1/3
- Limit of the function:
- 1/3
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Identical expressions
- log(twenty-seven)*x= one / three
- logarithm of (27) multiply by x equally 1 divide by 3
- logarithm of (twenty minus seven) multiply by x equally one divide by three
- log(27)x=1/3
- log27x=1/3
- log(27)*x=1 divide by 3
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Similar expressions
- cos(pi*(x-1)/3)=1/2
- logx27-log27x²=1
- log(3)x+log(9)x+log(27)x=5,5
- log3(x)-log9(x)-log27(x)=0,5
log(27)*x=1/3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Divide both parts of the equation by log(27)
We get the answer: x = 1/(9*log(3))
log(27)*x = 1/3
Expand brackets in the left part
log27x = 1/3
Divide both parts of the equation by log(27)
x = 1/3 / (log(27))
We get the answer: x = 1/(9*log(3))
Sum and product of roots
[src]
sum
1 -------- 9*log(3)
$$\frac{1}{9 \log{\left(3 \right)}}$$
=
1 -------- 9*log(3)
$$\frac{1}{9 \log{\left(3 \right)}}$$
product
1 -------- 9*log(3)
$$\frac{1}{9 \log{\left(3 \right)}}$$
=
1 -------- 9*log(3)
$$\frac{1}{9 \log{\left(3 \right)}}$$
1/(9*log(3))
Rapid solution
[src]
1
x1 = --------
9*log(3)
$$x_{1} = \frac{1}{9 \log{\left(3 \right)}}$$
x1 = 1/(9*log(3))
The graph