Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2*x^2+6*x+9=0
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Equation 2^2-x-1=x^2-5*x-(-1-x^2)
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Equation 10(x-9)=7
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Equation (x+2)^4+(x+2)^2-12=0
- Express {x} in terms of y where:
- 4*x-18*y=-14
- -14*x-1*y=3
- -6*x+2*y=-10
- 10*x-18*y=6
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Identical expressions
- log(three)x+log(nine)x+log(twenty-seven)x= five , five
- logarithm of (3)x plus logarithm of (9)x plus logarithm of (27)x equally 5,5
- logarithm of (three)x plus logarithm of (nine)x plus logarithm of (twenty minus seven)x equally five , five
- log3x+log9x+log27x=5,5
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Similar expressions
- log(3)x-log(9)x+log(27)x=5,5
- log(3)x+log(9)x-log(27)x=5,5
log(3)x+log(9)x+log(27)x=5,5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
log(3)*x + log(9)*x + log(27)*x = 11/2
$$x \log{\left(27 \right)} + \left(x \log{\left(3 \right)} + x \log{\left(9 \right)}\right) = \frac{11}{2}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Divide both parts of the equation by (x*log(3) + x*log(9) + x*log(27))/x
We get the answer: x = 11/(12*log(3))
log(3)*x+log(9)*x+log(27)*x = (11/2)
Expand brackets in the left part
log3x+log9x+log27x = (11/2)
Expand brackets in the right part
log3x+log9x+log27x = 11/2
Divide both parts of the equation by (x*log(3) + x*log(9) + x*log(27))/x
x = 11/2 / ((x*log(3) + x*log(9) + x*log(27))/x)
We get the answer: x = 11/(12*log(3))
Rapid solution
[src]
11
x1 = ---------
12*log(3)
$$x_{1} = \frac{11}{12 \log{\left(3 \right)}}$$
x1 = 11/(12*log(3))
Sum and product of roots
[src]
sum
11 --------- 12*log(3)
$$\frac{11}{12 \log{\left(3 \right)}}$$
=
11 --------- 12*log(3)
$$\frac{11}{12 \log{\left(3 \right)}}$$
product
11 --------- 12*log(3)
$$\frac{11}{12 \log{\left(3 \right)}}$$
=
11 --------- 12*log(3)
$$\frac{11}{12 \log{\left(3 \right)}}$$
11/(12*log(3))