Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- 4*x+13*y=13
- 17*x-19*y=1
- 9*x-18*y=6
- -1*x+19*y=-10
- Equation:
-
Equation cos(x)=1/3
-
Equation x^4-5x^2+4=0
-
Equation x^2-6x+8=0
-
Equation (x^2-9)^2+(x^2-2*x-15)^2=0
- Sum of series:
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13
- Canonical form:
- 13
- Derivative of:
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13
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Identical expressions
- four *x+ thirteen *y= thirteen
- 4 multiply by x plus 13 multiply by y equally 13
- four multiply by x plus thirteen multiply by y equally thirteen
- 4x+13y=13
-
Similar expressions
- 4*x-13*y=13
- (x^2+y^2-1)^3-x^2*y^3=0
Express x in terms of y where 4*x+13*y=13
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$4 x = 13 - 13 y$$
Divide both parts of the equation by 4
We get the answer: x = 13/4 - 13*y/4
4*x+13*y = 13
Looking for similar summands in the left part:
4*x + 13*y = 13
Move the summands with the other variables
from left part to right part, we given:
$$4 x = 13 - 13 y$$
Divide both parts of the equation by 4
x = 13 - 13*y / (4)
We get the answer: x = 13/4 - 13*y/4
Rapid solution
[src]
13 13*re(y) 13*I*im(y)
x1 = -- - -------- - ----------
4 4 4
$$x_{1} = - \frac{13 \operatorname{re}{\left(y\right)}}{4} - \frac{13 i \operatorname{im}{\left(y\right)}}{4} + \frac{13}{4}$$
x1 = -13*re(y)/4 - 13*i*im(y)/4 + 13/4