Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)-sin(x)=0
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Equation 5-2x=11-7(x+2)
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Equation -9(8-9x)=4x+5
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Equation sin(pi*x)=1
- Express {x} in terms of y where:
- 16*x+7*y=8
- -11*x+4*y=-8
- 17*x-11*y=2
- -14*x+1*y=3
- Graphing y =:
- 5-2x
- Integral of d{x}:
- 5-2x
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Identical expressions
- five - two x= eleven - seven (x+2)
- 5 minus 2x equally 11 minus 7(x plus 2)
- five minus two x equally eleven minus seven (x plus 2)
- 5-2x=11-7x+2
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Similar expressions
- 5+2x=11-7(x+2)
- 5-2*x=11-7*(x+2)
- (sqrt(5)-2)^x+(sqrt(5)+2)^x=18
- 5-2x=11-7*(x+2)
- (sqrt(5)+2)^x-1=(sqrt(5)-2)^x-1/x+1
- 11-7*(x+2)=0
- 5-2x=11+7(x+2)
- 5-2x=11-7(x-2)
- 4585-(2x+93)*34=1423
5-2x=11-7(x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 7 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -8$$
Divide both parts of the equation by 5
We get the answer: x = -8/5
5-2*x = 11-7*(x+2)
Expand brackets in the right part
5-2*x = 11-7*x-7*2
Looking for similar summands in the right part:
5 - 2*x = -3 - 7*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 7 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -8$$
Divide both parts of the equation by 5
x = -8 / (5)
We get the answer: x = -8/5
Sum and product of roots
[src]
sum
-8/5
$$- \frac{8}{5}$$
=
-8/5
$$- \frac{8}{5}$$
product
-8/5
$$- \frac{8}{5}$$
=
-8/5
$$- \frac{8}{5}$$
-8/5
The graph