sin(x)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
sin(x)=2- this is the simplest trigonometric equation
As right part of the equation
modulo =
True
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
The graph
x1 = pi - re(asin(2)) - I*im(asin(2))
x1=−re(asin(2))+π−iim(asin(2))
x2 = I*im(asin(2)) + re(asin(2))
x2=re(asin(2))+iim(asin(2))
x2 = re(asin(2)) + i*im(asin(2))
Sum and product of roots
[src]
pi - re(asin(2)) - I*im(asin(2)) + I*im(asin(2)) + re(asin(2))
(re(asin(2))+iim(asin(2)))+(−re(asin(2))+π−iim(asin(2)))
(pi - re(asin(2)) - I*im(asin(2)))*(I*im(asin(2)) + re(asin(2)))
(re(asin(2))+iim(asin(2)))(−re(asin(2))+π−iim(asin(2)))
-(I*im(asin(2)) + re(asin(2)))*(-pi + I*im(asin(2)) + re(asin(2)))
−(re(asin(2))+iim(asin(2)))(−π+re(asin(2))+iim(asin(2)))
-(i*im(asin(2)) + re(asin(2)))*(-pi + i*im(asin(2)) + re(asin(2)))
x1 = 1.5707963267949 + 1.31695789692482*i
x2 = 1.5707963267949 - 1.31695789692482*i
x2 = 1.5707963267949 - 1.31695789692482*i