Mister Exam
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How to use it?
- Express {x} in terms of y where:
- 10*x+9*y=-4
- -12*x+3*y=-9
- -10*x-16*y=-6
- 16*x+7*y=8
- Equation:
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Equation (x+10)^2=(5-x)^2
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Equation tg(x)=0
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Equation sinx=1/2
-
Equation 3x^2+6x=0
- Derivative of:
- -4
- Integral of d{x}:
-
-4
- Limit of the function:
- -4
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Identical expressions
- ten *x+ nine *y=- four
- 10 multiply by x plus 9 multiply by y equally minus 4
- ten multiply by x plus nine multiply by y equally minus four
- 10x+9y=-4
-
Similar expressions
- 10*x+9*y=+4
- 10*x-9*y=-4
Express x in terms of y where 10*x+9*y=-4
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$10 x = - 9 y - 4$$
Divide both parts of the equation by 10
We get the answer: x = -2/5 - 9*y/10
10*x+9*y = -4
Looking for similar summands in the left part:
9*y + 10*x = -4
Move the summands with the other variables
from left part to right part, we given:
$$10 x = - 9 y - 4$$
Divide both parts of the equation by 10
x = -4 - 9*y / (10)
We get the answer: x = -2/5 - 9*y/10
Rapid solution
[src]
2 9*re(y) 9*I*im(y)
x1 = - - - ------- - ---------
5 10 10
$$x_{1} = - \frac{9 \operatorname{re}{\left(y\right)}}{10} - \frac{9 i \operatorname{im}{\left(y\right)}}{10} - \frac{2}{5}$$
x1 = -9*re(y)/10 - 9*i*im(y)/10 - 2/5