Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-8*x+17=0
- Equation x^2-y^2=0
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Equation x+19=12
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Equation 4-6(x+2)=3-5x
- Express {x} in terms of y where:
- 17*x+20*y=-12
- 11*x-20*y=-10
- -7*x-13*y=5
- 19*x+1*y=0
- Graphing y =:
- 5-2x
- Integral of d{x}:
- 5-2x
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Identical expressions
- five - two x= eleven - seven *(x+2)
- 5 minus 2x equally 11 minus 7 multiply by (x plus 2)
- five minus two x equally eleven minus seven multiply by (x plus 2)
- 5-2x=11-7(x+2)
- 5-2x=11-7x+2
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Similar expressions
- 5-2x=11+7*(x+2)
- (2*x+3)/3-(5*x+13)/6+(5-2*x)/2=6
- 5-2x=11-7*(x-2)
- (282/5)-(2*x-(193/50))=(2013/50)
- 5+2x=11-7*(x+2)
5-2x=11-7*(x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 7 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -8$$
Divide both parts of the equation by 5
We get the answer: x = -8/5
5-2*x = 11-7*(x+2)
Expand brackets in the right part
5-2*x = 11-7*x-7*2
Looking for similar summands in the right part:
5 - 2*x = -3 - 7*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 7 x - 8$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = -8$$
Divide both parts of the equation by 5
x = -8 / (5)
We get the answer: x = -8/5
Sum and product of roots
[src]
sum
-8/5
$$- \frac{8}{5}$$
=
-8/5
$$- \frac{8}{5}$$
product
-8/5
$$- \frac{8}{5}$$
=
-8/5
$$- \frac{8}{5}$$
-8/5
The graph