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How to use it?
- Equation:
- Equation 3x-3x2=-26x=10
- Equation x/24+11/24=23/24
- Equation x^4+81=0
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Equation 4x+37+5x=937
- Express {x} in terms of y where:
- 5*x-5*y=20
- 8*x-7*y=-13
- 9*x+18*y=6
- 15*x-15*y=16
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Identical expressions
- 3x-3x2=-26x= ten
- 3x minus 3x2 equally minus 26x equally 10
- 3x minus 3x2 equally minus 26x equally ten
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Similar expressions
- 3*x-3*x^2-1=0
- 3x-3x2=+26x=10
- 3x+3x2=-26x=10
- 9^x-2*6^x+2*4^x-2*2^x+1=0
- 13x-3x^2=-14
- -1-3*x-3*(x^2)-(x^3)=0
- -5x^2-2x+6=3x-3x^2+9-(2+2x^2)
- 18-2(6x-4)=-3+6(x+7)
- (x-2)(6x+1)/6-(3x-1)(x+1)/3=-5
3x-3x2=-26x=10 equation
The teacher will be very surprised to see your correct solution 😉
The solution
The graph
Rapid solution
[src]
3*re(x2) 3*I*im(x2)
x1 = -------- + ----------
29 29
$$x_{1} = \frac{3 \operatorname{re}{\left(x_{2}\right)}}{29} + \frac{3 i \operatorname{im}{\left(x_{2}\right)}}{29}$$
x1 = 3*re(x2)/29 + 3*i*im(x2)/29
Sum and product of roots
[src]
sum
3*re(x2) 3*I*im(x2) -------- + ---------- 29 29
$$\frac{3 \operatorname{re}{\left(x_{2}\right)}}{29} + \frac{3 i \operatorname{im}{\left(x_{2}\right)}}{29}$$
=
3*re(x2) 3*I*im(x2) -------- + ---------- 29 29
$$\frac{3 \operatorname{re}{\left(x_{2}\right)}}{29} + \frac{3 i \operatorname{im}{\left(x_{2}\right)}}{29}$$
product
3*re(x2) 3*I*im(x2) -------- + ---------- 29 29
$$\frac{3 \operatorname{re}{\left(x_{2}\right)}}{29} + \frac{3 i \operatorname{im}{\left(x_{2}\right)}}{29}$$
=
3*re(x2) 3*I*im(x2) -------- + ---------- 29 29
$$\frac{3 \operatorname{re}{\left(x_{2}\right)}}{29} + \frac{3 i \operatorname{im}{\left(x_{2}\right)}}{29}$$
3*re(x2)/29 + 3*i*im(x2)/29