Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation 5*x^2-45=0
-
Equation 16*x^3+8*x^2+x=0
-
Equation 3/5*y=29/10-1/5
-
Equation x^2+7*x+12=0
- Express {x} in terms of y where:
- -3*x-10*y=1
- -4*x-13*y=-14
- -2*x+20*y=-3
- 6*x+1*y=8
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Identical expressions
- -5x^ two - two x+ six =3x-3x^ two + nine -(two +2x^2)
- minus 5x squared minus 2x plus 6 equally 3x minus 3x squared plus 9 minus (2 plus 2x squared )
- minus 5x to the power of two minus two x plus six equally 3x minus 3x to the power of two plus nine minus (two plus 2x squared )
- -5x2-2x+6=3x-3x2+9-(2+2x2)
- -5x2-2x+6=3x-3x2+9-2+2x2
- -5x²-2x+6=3x-3x²+9-(2+2x²)
- -5x to the power of 2-2x+6=3x-3x to the power of 2+9-(2+2x to the power of 2)
- -5x^2-2x+6=3x-3x^2+9-2+2x^2
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Similar expressions
- -5x^2-2x+6=3x-3x^2+9+(2+2x^2)
- -5x^2+2x+6=3x-3x^2+9-(2+2x^2)
- -5x^2-2x+6=3x-3x^2+9-(2-2x^2)
- -5x^2-2x+6=3x+3x^2+9-(2+2x^2)
- -5x^2-2x+6=3x-3x^2-9-(2+2x^2)
- 5x^2-2x+6=3x-3x^2+9-(2+2x^2)
- -5x^2-2x-6=3x-3x^2+9-(2+2x^2)
-5x^2-2x+6=3x-3x^2+9-(2+2x^2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
2 2 2 - 5*x - 2*x + 6 = 3*x - 3*x + 9 + -2 - 2*x
$$\left(- 5 x^{2} - 2 x\right) + 6 = \left(- 2 x^{2} - 2\right) + \left(\left(- 3 x^{2} + 3 x\right) + 9\right)$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x^{2} - 2 x = - 5 x^{2} + 3 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x^{2} + \left(-5\right) x = \left(-5\right) x^{2} + 1$$
Divide both parts of the equation by (-5*x - 5*x^2)/x
We get the answer: x = -1/5
-5*x^2-2*x+6 = 3*x-3*x^2+9-(2+2*x^2)
Expand brackets in the right part
-5*x^2-2*x+6 = 3*x-3*x^2+9-2-2*x-2
Looking for similar summands in the right part:
6 - 5*x^2 - 2*x = 7 - 5*x^2 + 3*x
Move free summands (without x)
from left part to right part, we given:
$$- 5 x^{2} - 2 x = - 5 x^{2} + 3 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x^{2} + \left(-5\right) x = \left(-5\right) x^{2} + 1$$
Divide both parts of the equation by (-5*x - 5*x^2)/x
x = 1 - 5*x^2 / ((-5*x - 5*x^2)/x)
We get the answer: x = -1/5
Sum and product of roots
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sum
-1/5
$$- \frac{1}{5}$$
=
-1/5
$$- \frac{1}{5}$$
product
-1/5
$$- \frac{1}{5}$$
=
-1/5
$$- \frac{1}{5}$$
-1/5