Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- 8*x-7*y=-13
- 15*x-15*y=16
- 9*x+18*y=6
- (x^2+y^2-1)^3+x^2*y^3=0
- Equation:
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Equation 8*cos(x)+sin(7*x)-16*x=x^3+8
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Equation x^4+8x^2-9=0
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Equation (sin2Пx)/(4x-1)=1/(4x-1)
-
Equation sin((2*x+2*pi)/3)*cos((4*x+pi)/3)-cos(2*x)=sin(x)^2/cos(-(-pi)/3)
- Sum of series:
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-13
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Identical expressions
- eight *x- seven *y=- thirteen
- 8 multiply by x minus 7 multiply by y equally minus 13
- eight multiply by x minus seven multiply by y equally minus thirteen
- 8x-7y=-13
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Similar expressions
- (x^2+y^2-1)^3+x^2*y^3=0
- 8*x+7*y=-13
- 8*x-7*y=+13
- (x^2+y^2-1)^3-x^2*y^3=0
Express x in terms of y where 8*x-7*y=-13
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$8 x = 7 y - 13$$
Divide both parts of the equation by 8
We get the answer: x = -13/8 + 7*y/8
8*x-7*y = -13
Looking for similar summands in the left part:
-7*y + 8*x = -13
Move the summands with the other variables
from left part to right part, we given:
$$8 x = 7 y - 13$$
Divide both parts of the equation by 8
x = -13 + 7*y / (8)
We get the answer: x = -13/8 + 7*y/8
Rapid solution
[src]
13 7*re(y) 7*I*im(y)
x1 = - -- + ------- + ---------
8 8 8
$$x_{1} = \frac{7 \operatorname{re}{\left(y\right)}}{8} + \frac{7 i \operatorname{im}{\left(y\right)}}{8} - \frac{13}{8}$$
x1 = 7*re(y)/8 + 7*i*im(y)/8 - 13/8