The teacher will be very surprised to see your correct solution 😉

Detail solution

Given the linear equation:

Looking for similar summands in the left part:

Move the summands with the other variables

from left part to right part, we given:

$$5 x = 5 y + 20$$

Divide both parts of the equation by 5

We get the answer: x = 4 + y

5*x-5*y = 20

Looking for similar summands in the left part:

-5*y + 5*x = 20

Move the summands with the other variables

from left part to right part, we given:

$$5 x = 5 y + 20$$

Divide both parts of the equation by 5

x = 20 + 5*y / (5)

We get the answer: x = 4 + y

Rapid solution
[src]

x1 = 4 + I*im(y) + re(y)

$$x_{1} = \operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} + 4$$

x1 = re(y) + i*im(y) + 4