3 sin (x)
sin(x)^3
Let u=sin(x)u = \sin{\left(x \right)}u=sin(x).
Apply the power rule: u3u^{3}u3 goes to 3u23 u^{2}3u2
Then, apply the chain rule. Multiply by ddxsin(x)\frac{d}{d x} \sin{\left(x \right)}dxdsin(x):
The derivative of sine is cosine:
The result of the chain rule is:
The answer is:
2 3*sin (x)*cos(x)
/ 2 2 \ 3*\- sin (x) + 2*cos (x)/*sin(x)
/ 2 2 \ 3*\- 7*sin (x) + 2*cos (x)/*cos(x)