Mister Exam

Derivative of sin³(x/3)

Function f() - derivative -N order at the point
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The graph:

from to

Piecewise:

The solution

You have entered [src]
   3/x\
sin |-|
    \3/
sin3(x3)\sin^{3}{\left(\frac{x}{3} \right)}
sin(x/3)^3
Detail solution
  1. Let u=sin(x3)u = \sin{\left(\frac{x}{3} \right)}.

  2. Apply the power rule: u3u^{3} goes to 3u23 u^{2}

  3. Then, apply the chain rule. Multiply by ddxsin(x3)\frac{d}{d x} \sin{\left(\frac{x}{3} \right)}:

    1. Let u=x3u = \frac{x}{3}.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddxx3\frac{d}{d x} \frac{x}{3}:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: xx goes to 11

        So, the result is: 13\frac{1}{3}

      The result of the chain rule is:

      cos(x3)3\frac{\cos{\left(\frac{x}{3} \right)}}{3}

    The result of the chain rule is:

    sin2(x3)cos(x3)\sin^{2}{\left(\frac{x}{3} \right)} \cos{\left(\frac{x}{3} \right)}

  4. Now simplify:

    sin2(x3)cos(x3)\sin^{2}{\left(\frac{x}{3} \right)} \cos{\left(\frac{x}{3} \right)}


The answer is:

sin2(x3)cos(x3)\sin^{2}{\left(\frac{x}{3} \right)} \cos{\left(\frac{x}{3} \right)}

The graph
02468-8-6-4-2-10102-2
The first derivative [src]
   2/x\    /x\
sin |-|*cos|-|
    \3/    \3/
sin2(x3)cos(x3)\sin^{2}{\left(\frac{x}{3} \right)} \cos{\left(\frac{x}{3} \right)}
The second derivative [src]
/     2/x\        2/x\\    /x\
|- sin |-| + 2*cos |-||*sin|-|
\      \3/         \3//    \3/
------------------------------
              3               
(sin2(x3)+2cos2(x3))sin(x3)3\frac{\left(- \sin^{2}{\left(\frac{x}{3} \right)} + 2 \cos^{2}{\left(\frac{x}{3} \right)}\right) \sin{\left(\frac{x}{3} \right)}}{3}
The third derivative [src]
/       2/x\        2/x\\    /x\
|- 7*sin |-| + 2*cos |-||*cos|-|
\        \3/         \3//    \3/
--------------------------------
               9                
(7sin2(x3)+2cos2(x3))cos(x3)9\frac{\left(- 7 \sin^{2}{\left(\frac{x}{3} \right)} + 2 \cos^{2}{\left(\frac{x}{3} \right)}\right) \cos{\left(\frac{x}{3} \right)}}{9}