/1\ log|-| \x/
log(1/x)
Let u=1xu = \frac{1}{x}u=x1.
The derivative of log(u)\log{\left(u \right)}log(u) is 1u\frac{1}{u}u1.
Then, apply the chain rule. Multiply by ddx1x\frac{d}{d x} \frac{1}{x}dxdx1:
Apply the power rule: 1x\frac{1}{x}x1 goes to −1x2- \frac{1}{x^{2}}−x21
The result of the chain rule is:
The answer is:
-1 --- x
1 -- 2 x
-2 --- 3 x