Mister Exam

Sum of series sin2x



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The solution

You have entered [src]
  n           
 __           
 \ `          
  )   sin(2*x)
 /_,          
n = 1         
n=1nsin(2x)\sum_{n=1}^{n} \sin{\left(2 x \right)}
Sum(sin(2*x), (n, 1, n))
The answer [src]
n*sin(2*x)
nsin(2x)n \sin{\left(2 x \right)}
n*sin(2*x)

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