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  • Sum of series:
  • (3/4)^n (3/4)^n
  • 1/((2n-1)*(2n+1)) 1/((2n-1)*(2n+1))
  • 1/(n*(n+3)) 1/(n*(n+3))
  • (5/6)^n (5/6)^n
  • Identical expressions

  • sin^ two (x)/(x^(one / three))
  • sinus of squared (x) divide by (x to the power of (1 divide by 3))
  • sinus of to the power of two (x) divide by (x to the power of (one divide by three))
  • sin2(x)/(x(1/3))
  • sin2x/x1/3
  • sin²(x)/(x^(1/3))
  • sin to the power of 2(x)/(x to the power of (1/3))
  • sin^2x/x^1/3
  • sin^2(x) divide by (x^(1 divide by 3))

Sum of series sin^2(x)/(x^(1/3))



=

The solution

You have entered [src]
  oo         
____         
\   `        
 \       2   
  \   sin (x)
   )  -------
  /    3 ___ 
 /     \/ x  
/___,        
n = 1        
$$\sum_{n=1}^{\infty} \frac{\sin^{2}{\left(x \right)}}{\sqrt[3]{x}}$$
Sum(sin(x)^2/x^(1/3), (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{\sin^{2}{\left(x \right)}}{\sqrt[3]{x}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{\sin^{2}{\left(x \right)}}{\sqrt[3]{x}}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty} 1$$
Let's take the limit
we find
True

False
The answer [src]
      2   
oo*sin (x)
----------
  3 ___   
  \/ x    
$$\frac{\infty \sin^{2}{\left(x \right)}}{\sqrt[3]{x}}$$
oo*sin(x)^2/x^(1/3)

    Examples of finding the sum of a series