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Sum of series:
x^n/n
1/(4n^2-1)
((-1)^(n+1))/(2^n)
sen(ix)
Identical expressions
one * six thousand, nine hundred * three
1 multiply by 6900 multiply by 3
one multiply by six thousand, nine hundred multiply by three
169003

Sum of series/ 1*6900*3

Sum of series 169003

The solution

You have entered [src]

$$\sum_{i=201}^{n} 20700$$

Sum(20700, (i, 201, n))

The rate of convergence of the power series

The answer [src]

-4140000 + 20700*n

$$20700 n - 4140000$$

-4140000 + 20700*n

The graph

Sum of series 1*6900*3

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```