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(n-1)/2^(n+1)

Sum of series (n-1)/2^(n+1)



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The solution

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  oo        
____        
\   `       
 \    n - 1 
  \   ------
  /    n + 1
 /    2     
/___,       
n = 1       
n=1n12n+1\sum_{n=1}^{\infty} \frac{n - 1}{2^{n + 1}}
Sum((n - 1)/2^(n + 1), (n, 1, oo))
The radius of convergence of the power series
Given number:
n12n+1\frac{n - 1}{2^{n + 1}}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=2n1(n1)a_{n} = 2^{- n - 1} \left(n - 1\right)
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn(2n12n+2n1n)1 = \lim_{n \to \infty}\left(\frac{2^{- n - 1} \cdot 2^{n + 2} \left|{n - 1}\right|}{n}\right)
Let's take the limit
we find
False

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50.00.5
The answer [src]
1/2
12\frac{1}{2}
1/2
Numerical answer [src]
0.500000000000000000000000000000
0.500000000000000000000000000000
The graph
Sum of series (n-1)/2^(n+1)

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