Mister Exam

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How to use it?
Sum of series:
1/(n(n+1))
12/(n^2+4*n+3)
(1-5/n)^n
i^n
Limit of the function:
i^n
Identical expressions
i^n
i to the power of n
in

Sum of series/ i^n

Sum of series i^n

The solution

You have entered [src]

  oo    
 ___    
 \  `   
  \    n
  /   I 
 /__,   
n = 1

\sum_{n=1}^{\infty} i^{n}

Sum(i^n, (n, 1, oo))

The radius of convergence of the power series

Given number:

i^{n}

It is a series of species

a_{n} \left(c x - x_{0}\right)^{d n}

- power series.
The radius of convergence of a power series can be calculated by the formula:

R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}

In this case

a_{n} = 1

and

x_{0} = - i

,

d = 1

,

c = 0

then

R = \tilde{\infty} \left(- i + \lim_{n \to \infty} 1\right)

Let's take the limit
we find

False

Numerical answer

The series diverges

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```