Mister Exam

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Sum of series:
1/3
(-1)^n/sqrt(n)
1/(n*(n+1)*(n+2))
(x^z-m^x)(y^z-m^y)
Limit of the function:
(-1)^n/sqrt(n)
Identical expressions
(- one)^n/sqrt(n)
( minus 1) to the power of n divide by square root of (n)
( minus one) to the power of n divide by square root of (n)
(-1)^n/√(n)
(-1)n/sqrt(n)
-1n/sqrtn
-1^n/sqrtn
(-1)^n divide by sqrt(n)
Similar expressions
(1)^n/sqrt(n)

Sum of series/ (-1)^n/sqrt(n)

Sum of series (-1)^n/sqrt(n)

The solution

You have entered [src]

  oo       
____       
\   `      
 \        n
  \   (-1) 
   )  -----
  /     ___
 /    \/ n 
/___,      
n = 1

$$\sum_{n=1}^{\infty} \frac{\left(-1\right)^{n}}{\sqrt{n}}$$

Sum((-1)^n/sqrt(n), (n, 1, oo))

The radius of convergence of the power series

Given number:
$$\frac{\left(-1\right)^{n}}{\sqrt{n}}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{1}{\sqrt{n}}$$
and
$$x_{0} = 1$$
,
$$d = 1$$
,
$$c = 0$$
then
$$R = \tilde{\infty} \left(1 + \lim_{n \to \infty}\left(\frac{\sqrt{n + 1}}{\sqrt{n}}\right)\right)$$
Let's take the limit
we find

False

The rate of convergence of the power series

The graph

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```

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How to use it?

Identical expressions

Similar expressions

Sum of series (-1)^n/sqrt(n)

The solution

Examples of finding the sum of a series