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Sum of series ln(k+1)/n



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The solution

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  oo            
 ___            
 \  `           
  \   log(k + 1)
   )  ----------
  /       n     
 /__,           
n = 1           
n=1log(k+1)n\sum_{n=1}^{\infty} \frac{\log{\left(k + 1 \right)}}{n}
Sum(log(k + 1)/n, (n, 1, oo))
The radius of convergence of the power series
Given number:
log(k+1)n\frac{\log{\left(k + 1 \right)}}{n}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=log(k+1)na_{n} = \frac{\log{\left(k + 1 \right)}}{n}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn(n+1n)1 = \lim_{n \to \infty}\left(\frac{n + 1}{n}\right)
Let's take the limit
we find
True

False
The answer [src]
oo*log(1 + k)
log(k+1)\infty \log{\left(k + 1 \right)}
oo*log(1 + k)

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