The perfect square
Let's highlight the perfect square of the square three-member
$$\left(y^{4} + 8 y^{2}\right) + 6$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 8$$
$$c = 6$$
Then
$$m = 4$$
$$n = -10$$
So,
$$\left(y^{2} + 4\right)^{2} - 10$$
/ ____________\ / ____________\ / ____________\ / ____________\
| / ____ | | / ____ | | / ____ | | / ____ |
\x + I*\/ 4 - \/ 10 /*\x - I*\/ 4 - \/ 10 /*\x + I*\/ 4 + \/ 10 /*\x - I*\/ 4 + \/ 10 /
$$\left(x - i \sqrt{4 - \sqrt{10}}\right) \left(x + i \sqrt{4 - \sqrt{10}}\right) \left(x + i \sqrt{\sqrt{10} + 4}\right) \left(x - i \sqrt{\sqrt{10} + 4}\right)$$
(((x + i*sqrt(4 - sqrt(10)))*(x - i*sqrt(4 - sqrt(10))))*(x + i*sqrt(4 + sqrt(10))))*(x - i*sqrt(4 + sqrt(10)))
General simplification
[src]
$$y^{4} + 8 y^{2} + 6$$
Rational denominator
[src]
$$y^{4} + 8 y^{2} + 6$$
Assemble expression
[src]
$$y^{4} + 8 y^{2} + 6$$
Combining rational expressions
[src]
$$y^{2} \left(y^{2} + 8\right) + 6$$