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How do you (x^2-6*x+8)/(x-4) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2          
x  - 6*x + 8
------------
   x - 4    
$$\frac{\left(x^{2} - 6 x\right) + 8}{x - 4}$$
(x^2 - 6*x + 8)/(x - 4)
General simplification [src]
-2 + x
$$x - 2$$
-2 + x
Fraction decomposition [src]
-2 + x
$$x - 2$$
-2 + x
Trigonometric part [src]
     2      
8 + x  - 6*x
------------
   -4 + x   
$$\frac{x^{2} - 6 x + 8}{x - 4}$$
(8 + x^2 - 6*x)/(-4 + x)
Powers [src]
     2      
8 + x  - 6*x
------------
   -4 + x   
$$\frac{x^{2} - 6 x + 8}{x - 4}$$
(8 + x^2 - 6*x)/(-4 + x)
Common denominator [src]
-2 + x
$$x - 2$$
-2 + x
Combinatorics [src]
-2 + x
$$x - 2$$
-2 + x
Combining rational expressions [src]
8 + x*(-6 + x)
--------------
    -4 + x    
$$\frac{x \left(x - 6\right) + 8}{x - 4}$$
(8 + x*(-6 + x))/(-4 + x)
Numerical answer [src]
(8.0 + x^2 - 6.0*x)/(-4.0 + x)
(8.0 + x^2 - 6.0*x)/(-4.0 + x)
Assemble expression [src]
     2      
8 + x  - 6*x
------------
   -4 + x   
$$\frac{x^{2} - 6 x + 8}{x - 4}$$
(8 + x^2 - 6*x)/(-4 + x)
Rational denominator [src]
     2      
8 + x  - 6*x
------------
   -4 + x   
$$\frac{x^{2} - 6 x + 8}{x - 4}$$
(8 + x^2 - 6*x)/(-4 + x)